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Find the last digit of 2 87

WebJan 2, 2015 · 1 Answer. Sorted by: 1. if it's a string you want the last two characters, Else if it;s an integer doing %100 first storing the result in an int and then doing %10 on that is about as efficient as it gets. ( short might work better than int here, might not) integers are stored as binary numbers and the CPU can't see the 'last base 10 digit ... WebJun 18, 2024 · 8. Problem is easy to solve once you realize that the last digits of powers form a cycle. For example: 2: 2, 4, 8, 6, 2, 4 3: 3, 9, 7, 1, 3, 9. With that in mind you can create the cycle first and then just index it with modulo of n2: def last_digit (n1, n2): if n2 == 0: return 1 cycle = [n1 % 10] while True: nxt = (cycle [-1] * n1) % 10 if nxt ...

What is the last two digits of 65*29*37*63*71*87*62

Web42 166 = (2 × 21) 166. The last two digits of 76 n where n is a positive integer will be 76. Also, for numbers with the last two digits as 24, the square of the number will have 76 as the last digit. 2 10 ends with 24, ⇒ 2 166 21 166 = (2 10) 16 × 2 6 × 21 166. The 10s place will be the unit digit of the result of the multiplication of 10s ... WebLet (87) 75 63 55 = (87) xwhere x = (75) 63 55 = (87) odd∵ Cyclicity of 7 is 4∴ To find the last digit we have to find the remainder when x is divided by 4x = (75) oddpower = (76−1) oddpowerWhere x is divided by 4 so remainder will be -1 or 3 but remainder should be always positiveTherefore the last digit of (87) 75 63 55 will be (7) 3 ... bucher conjugaison https://erikcroswell.com

c - Finding the last 10 digits of 2^n - Stack Overflow

WebFind the last two digits of 87 474. 87 474 = 87 472 × 87 2 = (87 4) 118 × 87 2 = (69 × 69) 118 × 69 (The last two digits of 87 2 are 69) = 61 118 × 69 = 81 × 69 = 89. If you … WebThe last digit of 32^33 is equal to last digit of 2^33. Because only last digit matters for multiplying, for calculating the last digit of answer. And now, you can calculate 2^33 by … WebSo you want to access the digits in a integer like elements in a list; easiest way I can think of is: n = 56789 lastdigit = int (repr (n) [-1]) # > 9 Convert n into a string, accessing last element then use int constructor to convert back into integer. For a Floating point number: bucher contemporain

python - How to check last digit of number - Stack Overflow

Category:Daily Challenge #250 - Last Digit of a Large Number

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Find the last digit of 2 87

Find the three last digits of 7⁹⁹⁹⁹? - Quora

WebAug 1, 2010 · This widget will calculate the last digit of a number.The last digit number is used in Pattern of Power that is published in curiousmath.com. Send feedback Visit … WebFeb 1, 2024 · To find the last digit number in a multiplication, multiply only digit place numbers of a given series. Calculation: 81 × 82 × 83 × 85 × 86 × 87 × 88 × 89 ⇒ Multiplying 1×2×3×5×... ⇒ We will get zero '0' at the digit place ∴ We will obtain 0 at the digit place after multiplying the given numbers. Download Solution PDF Share on Whatsapp

Find the last digit of 2 87

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WebThe logic is first to convert the given value to a string and then convert it into the list to call the last digit by calling the -1 index. After that, convert it into an integer to wrap it up. val … WebApr 16, 2024 · step 1:- conversion. 8^33 = (2^3)^110. = (2)^330. step 2:- (2^10)^33 has odd power so, we take 24 as the last digit. So, Last two non zero digits of 8^330 are 24. …

WebMar 17, 2024 · To find last digit of a number, we use modulo operator %. When modulo divided by 10 returns its last digit. Suppose if n = 1234. then last Digit = n % 10 => 4. … WebOct 14, 2009 · For example, let’s find the last digit of 2 2009. , so the base power of two is 2 1+0 = 2 1 = 2. Trivially, we can see the ending digit is 2. For the last two digits of 2 2009, compute . The base power of two is 2 2+7 = 2 9, which is small enough to compute directly: 512. The last two digits are 12.

WebSep 29, 2015 · So +1. 7 4 ≡ 01 ( mod 100) ( 7 4) 502 ≡ ( 01) 502 ( mod 100) 7 2008 ≡ 01 ( mod 100) . Hence the last two digits are 01. Hint: 7 2008 = 49 1004 = ( 50 − 1) 1004. … WebMay 21, 2024 · Step-by-step explanation: gives unit digit as 6 because 6 raised to any power will give 6 only. whereas, gives unit digit as 9 because the cyclicity of 7 is 4 and when 42 is divided by 4 gives remainder 2 and value at 2nd place in cycle of 7 is 9. so 9*6 = 54. so unit digit will be 4. Advertisement.

WebMay 28, 2024 · Take the final character of the first string, and convert to a number. Take the final 2 characters of the second string, and convert to a number. These numbers can be supplied instead of the original arguments. But if the input is supposed to look like: (2^200) (2^300) then that turns into a parsing problem!

WebJan 27, 2024 · To find 17 − 2 m o d 100 we note first that 17 ⋅ 3 = 1 m o d 10. Then, we only have to solve. 17 ⋅ ( 10 x + 3) = 1 m o d 100. for x ∈ [ 0, 9] ∩ Z, in order to find the … extended stay hotel oaklandWebThe last digit of the number obtained by multiplying the numbers 81×82×83×84×85×86×87×88×89 will be A 9 B 7 C 2 Solution The correct option is B 0 … extended stay hotel near englewood floridaWebMay 21, 2024 · Step-by-step explanation: gives unit digit as 6 because 6 raised to any power will give 6 only. whereas, gives unit digit as 9 because the cyclicity of 7 is 4 and when 42 … extended stay hotel ocean city mdWebMar 24, 2024 · A simple solution is to find n-th Fibonacci number and print its last two digit. But N can be very large, so it wouldn’t work. A better solution is to use the fact that after 300-th Fibonacci number last two digits starts repeating. 1) Find m = n % 300. 2) Return m-th Fibonacci number. extended stay hotel oceanside caWebJun 25, 2024 · Find the last two digits of 51 456 × 61 567. Solution: The last two digits of 51 456 will be 01 and the last two digits of 61 567 will be 21. Therefore, the last two … extended stay hotel olympia waWebJan 14, 2024 · To find the last 2 digits of 2^n, ignore all digits except last 2 digits. 1. 2*2 = 4 2. 4*2 = 8 3. 8*2 = 16 4. 16*2 = 32 5. 32*2 = 64 6. 64*2 = 128 (Consider last 2 digits) 7. 28*2 = 56 8. 56*2 = 112 (Consider last 2 digits) 9. 12*2 = 24 ... n-1 iterations. Similarly, to find the last 10 digits of 2^n, consider just last 10 digits at each ... extended stay hotel nycWebNov 17, 2014 · The last two digits are 81 (6 × 3 = 18, so the tens digit will be 8 and last digit will be 1) Find the last two digits of 33 288. 33 288 = ( 33 4) 72. Now 33 4 ends in 21 ( 33 4 = 33 2 × 33 2 = 1089 × 1089 = xxxxx21) therefore, … extended stay hotel norwalk ct